Verified Answer :

RedRicin

Draw a right triangle.

\(tan(theta) = \frac{opposite}{adjacent}\)

\(tan(theta) = \frac{10}{14}\)

Arctangent (tan^-1) can be used to find theta.

\(tan^{-1}(\frac{10}{14})=theta\)

\(theta\ is\ approx\ \boxed{36\ degrees}\)

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