The Area of triangle is numerically equals to the half of area of parallelogram.
We have, the area of triangle is the half of product of its Base and Height.
\(A=\dfrac{1}{2}\ \rm Base\times\rm Height\)....(1).
Similarly, the Area of parallelogram is the product of its Base And Height.
\(A=\rm Base\times Height\)....(2).
From equation (1) and equation (2), it is clear that the area of triangle is half of the area of parallelogram.
Hence we can say that,
\(\rm Area(triangle)=\dfrac{1}{2}\rm Area (parallelogram)\).
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