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Verified Answer :

irspow

This is a geometric sequence because it has a common ratio, denoted r, meaning that each term is a multiple of the previous term.

\(a(n)=ar^{n-1}\), a=initial term, r=common ratio, n=term number

In this case a=\(1 \over 81\) and r=3 (because each term is 3 time the previous term) so

\(a(n)=(1/81)*3^{n-1}\)

So the 14th term is:

a(14)=(1/81)\(*3^{14}\)=59049