Answer: The order with respect to B is
Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
\(Rate=k[A]^x[B]^y\)
k= rate constant
x = order with respect to A
y = order with respect to B
n = x+y = Total order
a) From trial 1: \(20=k[0.20]^x[0.10]^y\) (1)
From trial 2: \(40=k[0.20]^x[0.20]^y\) (2)
Dividing 2 by 1 :\(\frac{40}{20}=\frac{k[0.20]^x[0.20]^y}{k[0.20]^x[0.10]^y}\)
\(2=2^y,2^1=2^y\) therefore y=1.
Thus order with respect to B is 1.
