What is the current in a parallel circuit which has two resistors (17.2 ohms and 22.4 ohms) and a power source of 6.0 volts?
We need to first find an equivalent resistance across the parallel circuit. that is found by the following equation
1/R1 + 1/R2 + ... = 1/Re
So...
1/17.2 + 1/22.4 = 1/Re
0.1021 = 1/Re
Re = 9.792 Ohms
Now use the Voltage equation V = IR
6 = I * 9.792
I = 6/9.792 = 0.613 Amps (or the current)
Answer : The current in a parallel circuit is, 0.6 A
Solution : Given,
Resistance, \(R_1\) = 17.2 ohm
Resistance, \(R_2\) = 22.4 ohm
Voltage = 6.0 V
First we have to calculate the total resistance in a circuit.
\(\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}\)
Now put all the given values in this expression, we get the total resistance in a circuit.
\(\frac{1}{R}=\frac{1}{17.2}+\frac{1}{22.4}\)
\(R=9.7\Omega\)
Now we have to calculate the current flowing in a parallel circuit.
Using ohm's law :
\(V=I\times R\)
where,
V = voltage
R = resistance
I = current
Now put all the given values in this formula, we get
\(6.0V=I\times 9.7\Omega\)
\(I=0.6A\)
Therefore, the current in a parallel circuit is, 0.6 A