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Verified Answer :

diene

f-g = 3x^2+1-(1-x) = 3x^2+x
(f-g)(2)=3*2^2 + 2 = 14

lublana

Answer:

B.14

Explanation:

We are given that

\(f(x)=3x^2+1\)

\(g(x)=1-x\)

We have to find the value of (f-g)(2)

\((f-g)(x)=f(x)-g(x)\)

\((f-g)(x)=3x^2+1-(1-x)=3x^2+1-1+x=3x^2+x\)

Substitute x=2

Then, we get

\((f-g)(2)=3(2)^2+2\)

\((f-g)(2)=12+2=14\)

Hence, the value of (f-g)(2)=14

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