Start off by combining like terms on the LHS (the terms with x in them).
So we get \(\frac{-1}{3}x+2x= \frac{-1}{3}x+ \frac{6}{3}x= \frac{-5}{3}x\)
Replacing this result with what we had before on the LHS, we get \(\frac{-5}{3}x=3 \frac{3}{4}= \frac{9}{4}\)
⇒Solve for x (divide both sides \(\frac{-5}{3}\))
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by \(\frac{3}{-5}\)
⇒\(x= \frac{9}{4}( \frac{3}{-5})\)
⇒\(x= -\frac{27}{20}=-1\frac{7}{20}\) ***This is a proper fraction
