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Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is the probability that either A or B occurs?


0.42


0.54


0.70


0.12

Verified Answer :

deplorablesrus

When you say either, you add both A and B
0.3+0.4=0.7
Your answer is 0.70 which means 70%

Answer:

The probability that either A or B occurs is 0.58

Step-by-step explanation:

P(A) = 0.3

P(B) =0.4

Since we are given that A and B are independent events

So, P(A∩B)=P(A)P(B)

P(A∩B)=0.30.4=0.12

So, P(A∪B)= P(A)+P(B)-P(A∩B)

P(A∪B)= 0.3+0.4-0.12

P(A∪B)=0.7-0.12

P(A∪B)=0.58

Now, the probability  that either A or B occurs (or both occurs) = P(A∪B)+P(A∩B)

= 0.58

Thus,the probability that either A or B occurs is 0.58

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