Answer:
\(4.92x10^{23}atoms,total\)
Explanation:
Hello,
The following mole-mass relationship is applied to find the atoms of P and O, taking into account that the molar mass of P2O5 is 78g/mol:
\(M_{P_2O_5}=31*2+16*5=78g/mol\\atoms_{P}=0.720gP_2O_5*\frac{1molP_2O_5}{78gP_2O_5} *\frac{2molP}{1molP_2O_5}*\frac{6.022x10^{23}atoms P}{1molP} =4.82x10^{22}atoms P\\atoms_{O}=0.720gP_2O_5*\frac{1molP_2O_5}{78gP_2O_5} *\frac{5molO}{1molP_2O_5}*\frac{6.022x10^{23}atoms O}{1molO} =1.2x10^{23}atoms O\)
Now, by adding those atoms, one concludes:
\(1.2x10^{23}atoms O+4.82x10^{22}atomsP=4.92x10^{23}atoms,total\)
Best regards.
