bewellplus.gsu.edu
britnyparker britnyparker
  • 10-02-2015
  • Mathematics
Answered

PLEASE HURRY!!!!!



What is the turning point of the graph of f(x) = |x – 4| ?

Verified Answer :

konrad509
konrad509 konrad509
  • 10-02-2015

\(f(x)=|x-4|\\ f'(x)=\text{sgn} (x-4)\\ \text{sgn} (x-4)=0\\ x-4=0\\ x=4\\\\\)

For \(x<4\) \(f'(x)<0\).
For \(x>4\) \(f'(x)>0\).
\(\Downarrow\\\)
At \(x=4\) there's turning point, which is equal \(|4-4|=|0|=0\).

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