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Verified Answer :

Azieq

x = 3y - 4
x + y = 16

3y - 4 + y = 16
4y = 20
y = 5

x = 3(5) - 4
x = 11

TaeKwonDoIsDead

Answer:

One number is 11 and another is 5

Step-by-step explanation:


One number is 4 less than 3 times another number:

If we let "one number" be x, and

"another number" be y, we can write:

\(x=3y-4\)


If their sum is 16:

This means if we add both the numbers, x & y, we get 16:

\(x+y=16\)


Now substituting equation 1 into equation 2, we can solve for y:

\(x+y=16\\(3y-4)+y=16\\3y-4+y=16\\4y=16+4\\4y=20\\y=\frac{20}{4}=5\)


Now substituting y=5 into equation 1, we can solve for x:

\(x=3y-4\\x=3(5)-4\\x=15-4\\x=11\)


Hence one number is 11 and another is 5

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