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You are given the polar curve r=1+cos(θ).

AList all of the points (r,θ) where the tangent line is horizontal. In entering your answer, list the points starting with the smallest value of r and limit yourself to r≥0 and 0≤θ<2π. If two or more points share the same value of r, list those starting with the smallest value of θ.
BList all of the points (r,θ) where the tangent line is vertical. In entering your answer, list the points starting with the smallest value of r and limit yourself to r≥0 and 0≤θ<2π. If two or more points share the same value of r, list those starting with the smallest value of θ..

Verified Answer :

MissPhiladelphia

For the answer to the question above,
 r = 1 + cos θ 

x = r cos θ 
x = ( 1 + cos θ) cos θ 
x = cos θ + cos^2 θ 
dx/dθ = -sin θ + 2 cos θ (-sin θ) 
dx/dθ = -sin θ - 2 cos θ sin θ 

y = r sin θ 
y = (1 + cos θ) sin θ 
y = sin θ + cos θ sin θ 
dy/dθ = cos θ - sin^2 θ + cos^2 θ 

dy/dx = (dy/dθ) / (dx/dθ) 
dy/dx = (cos θ - sin^2 θ + cos^2 θ)/ (-sin θ - 2 cos θ sin θ) 

For horizontal tangent line, dy/dθ = 0 

cos θ - sin^2 θ + cos^2 θ = 0 
cos θ - (1-cos^2 θ) + cos^2 θ = 0 
cos θ -1 + 2 cos^2 θ = 0 
2 cos^2 θ + cos θ -1 = 0 
Let y = cos θ 

2y^2+y-1=0 
2y^2+2y-y-1=0 
2y(y+1)-1(y+1)=0 
(y+1)(2y-1)=0 
y=-1 
y=1/2 

cos θ =-1 
θ = π 
cos θ =1/2 
θ = π/3 , 5π/3 

θ = π/3 , π, 5π/3 
when θ = π/3, r = 3/2 
when θ = π, r = 0 
when θ = 5π/3 , r = 3/2 
(3/2, π/3) and (3/2, 5π/3) give horizontal tangent lines 
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For horizontal tangent line, dx/dθ = 0 

-sin θ - 2 cos θ sin θ = 0 
-sin θ (1+ 2 cos θ ) = 0 
sin θ = 0 
θ = 0, π 

(1+ 2 cos θ ) =0 
cos θ =-1/2 
θ = 2π/3 
θ = 4π/3 

θ = 0, 2π/3 ,π, 4π/3 
when θ = 0, r=2 
when θ = 2π/3, r=1/2 
when θ = π, r=0 
when θ = 4π/3 , r=1/2 

(2,0) , (1/2, 2π/3) , (0, π), (1/2, 4π/3) 
At (2,0) there is a vertical tangent line

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