How much heat energy is required to raise the temperature of 0.368 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of copper is 0.0920 cal/(g⋅∘C) .
\(c_{Cu}=0,092\frac{cal}{g^{o}C}\\ \Delta T=60^{o}C-23^{o}C=37^{o}C\\ m=0,368kg=368g\\\\ Q=c\Delta Tm=0,092\frac{cal}{g^{o}C}*37^{o}C*368g=1252,672cal\\\\ Q=1252,672*4,184\approx 5241,2J\)
Answer:
1252.67 calories or 1.25Kcal
Explanation:
From
H= mcθ
m= mass of the body
c= specific heat capacity of the body
θ= change in temperature
m= 0.368K= 368g
c= 0.0920
θ= 60°C-23°C= 37°C
H= 368× 0.0920× 37
H= 1252.67 calories or 1.25Kcal