tangent line of f(x) = sec x @ (pi/3, 2)
the derivitive of sec(x) is sec(x)tan(x)find the slope at pi/3sec(pi/3)=2tan(pi/3)=√3sec(x)tan(x) at x=pi/3 is 2√3for slope=m and a point is (x1,y1)the equation isy-y1=m(x-x1)slope=2√3point=(pi/3,2)equation isy-2=2√3(x-pi/3)
