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Ziobro267
Ziobro267 Ziobro267
  • 09-12-2014
  • Mathematics
Answered

What is the 6th root of 256? ...left in radical notation

Verified Answer :

olemakpadu
olemakpadu olemakpadu
  • 09-12-2014

First of all we would break 256 into its simple factors.

2 / 256
2 / 128
2 /  64
2 /  32
2 /  16
2 /    8
2 /    4
2 /    2
        1.

Therefore   256 =  2 2 2 2 2 2 2 *2

Therefore sixth root of 256 = \(\sqrt[6]{2*2*2*2*2*2*2*2}\)

For every  six 2s we bring out one  out of the root.

= \(2\sqrt[6]{2*2}\)

= \(2\sqrt[6]{4}\)

That's our answer.

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