Answer:The value of \([OH^-]\) is \(1\time 10^{-11} M\)
Explanation;
The relation of ph and pOh is given as:
pH+pOH=14
pOH = 14 - 3 = 11
The pOH is defined as negative logarithm of hydroxide ion concentration.
\(11=-\log[OH^-]\)
\([OH^-]=1\times ^{-11}\)
The value of \([OH^-]\) is \(1\time 10^{-11} M\)
