Answer:
The value of v₀ is 32.
Step-by-step explanation:
The height of a football in feet x seconds after a player kicks it, is defined by the function
\(y=-16x^2+v_0x\)
It is given that the ball hits the ground 2 seconds after the player kicks it. The height is 0 at x=2.
\(0=-16(2)^2+v_0(2)\)
\(0=-64+2v_0\)
\(64=2v_0\)
Divide both sides by 2.
\(32=v_0\)
Therefore the value of v₀ is 32.
