Answer:
The value of x is 4/3.
Step-by-step explanation:
The given equation is
\(x^3=\frac{64}{27}\)
Taking cube root on both the sides.
\(x=\sqrt[3]{\frac{64}{27}}\)
Using the property of radical expression, we get
\(x=\frac{\sqrt[3]{64}}{\sqrt[3]{27}}\) \([\because \sqrt[3]{\frac{a}{b}}=\frac{\sqrt[3]{a}}{\sqrt[3]{b}}]\)
\(x=\frac{4}{3}\)
Therefore the value of x is 4/3.
