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An athlete competing in the long jump leaves the ground with a speed of 9.14 m/s at an angle of 55° with the vertical. what is the length of the athlete's jump if air resistance is of no significance?

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Answer:

8.01 m

Explanation:

Initial speed of the athlete, u = 9.14 m/s

angle from the vertical = 55°

⇒angle from the horizontal, θ = 90°-55° = 35°

length of the athlete's jump can be calculated using the formula:

\(R = \frac{u^2 sin2\theta}{g}\)

Substitute the values:

\(R =\frac{9.14^2sin (2\times 35^o)}{9.8}=8.01 m\)

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