Given triangle ABC, A = 120°, a = 8, b = 3; determine B to the nearest whole degree. Do not use a decimal point or extra spaces in the answer or it will be marked incorrect.
Answer:
∠B = 19°
Step-by-step explanation:
In the triangle ABC,
∠A = 120° side a = 8 and b = 3
We have to find angle B.
We will apply sine rule in this triangle
\(\frac{a}{sinA}=\frac{b}{sinB}\)
\(\frac{8}{sin120*}=\frac{3}{sinB}\)
8 sin B = 3 sin 120°
Sin b = \(\frac{3}{8}\) (sin 120°) = \(\frac{3\times 0.866}{8}\) = 0.3248
B = sin⁻¹ (0.3248)
= 18.95 ≈ 19°
Therefore, ∠B = 19° is the answer.