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calculista

we know that

When a product of two or more terms equals zero, then at least one of the terms must be zero

we have

\((x-6)(x+8)=0\)

We shall solve each term separately

First solution

\((x-6)=0\)

Adds \(6\) both sides

\((x-6)+6=0+6\)

\(x=6\)

Second solution

\((x+8)=0\)

Subtract \(8\) both sides

\((x+8)-8=0-8\)

\(x=-8\)

therefore

the answer is

The solutions are

\(x=6\)

\(x=-8\)

Answer:

The solution of the equation \((x -6)(x + 8) = 0\) is 6 and -8.

Step-by-step explanation:

Given :  The equation \((x-6)(x + 8) = 0\)

We have to find the solution to the given equation \((x -6)(x + 8) = 0\)

Consider the given equation \((x -6)(x + 8) = 0\)

Apply zero product rule, \(a\cdot b=0 \Rightarrow a=0 \ or \ b=0\)

Thus, \((x -6)(x + 8) = 0\) gives,

\((x -6)=0\) and \((x + 8) = 0\)

Simplify, we have,

\(x=6\) and \(x=-8\)

Thus, The solution of the equation \((x -6)(x + 8) = 0\) is 6 and -8.

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