factor 2x^3 -6x^2 -80x completely
\(2x^3 -6x^2 -80x \\ \\ 2x( \frac{2x^3}{2x} + \frac{-6x^2}{2x} + \frac{-80x}{2x} ) \\ \\ 2x(x^2 - 3x - 40) \\ \\ 2x(x - 8)(x + 5) \\ \\\)The answer is: 2x(x - 8)(x + 5).
