Answer:
\(y = \frac{-3}{2}x - 15\)
Step-by-step explanation:
We are given the following information in the question:
We are given equation of line:
\(-3x-2y = 30\)
The slope intercept form of a straight line is given by:
\(y = mx +c\)
where m is the slope of the line and c is the y intercept of the line.
Considering the given equation of the line:
\(-3x-2y = 30\\-2y = 3x + 30\\y = \displaystyle\frac{3x + 30}{-2}\\\\y = \frac{-3}{2}x - 15\)
is the required form of line.
where the slope of the given line is m = \(\frac{-3}{2}\) and y-intercept is c = -15
