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Jessica has been tracking the population of a town. The population was 8,230 last year and has been increasing by 1.25 times each year. How can Jessica develop a function to model this?


f(x) = (8230 • 1.25)x where 1.25 is the rate of growth


f(x) = 8230(1.25)x where 1.25 is the rate of growth


f(x) = 1.25(8230)x where 8230 is the rate of growth


f(x) = 8230(x)1.25 where 8230 is the rate of growth

Verified Answer :

HomertheGenius

Population at start : 8,230.
The rate of growth: r = 1.25
x - number of the years;
Answer:
B ) f ( x ) = 8,230 * ( 1.25 ) ^x where 1.25 is the rate of growth.

JeanaShupp

Answer: \(f(x) = 8230(1.25)^x\),  where 1.25 is the rate of growth .

Step-by-step explanation:

Given: Jessica has been tracking the population of a town.

The population was 8,230 last year and has been increasing by 1.25 times each year.

We know that the exponential growth function is given by :_

\(f(x)=Ab^x\), where A is the initial amount and b is the multiplicative rate of change in x years.

If we consider the population last year as initial population, then we get the following function:-

\(f(x) = 8230(1.25)^x\),  where 1.25 is the rate of growth .

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