volume of a right hexagonal pyramidd is \(\frac{ \sqrt{3} }{2}a^{2}h\) where a is the base side legnth and h=height
side legnth=12
height=36
subsitute
V=\(\frac{ \sqrt{3} }{2}(12^{2}) (36)\)
V=\(\frac{ \sqrt{3} }{2} (144)(36)\)
V=\(\frac{ \sqrt{3} }{2} (5184)\)
V=\(\frac{ 5184 \sqrt{3} }{2}\)
V=\(2592 \sqrt{3}\)
V=4489.48 cm^3
