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Verified Answer :

so you find pairs of factors and gropu
factor 96
96=2 times 2 times 2 times 2 times 2 times 3
group pairs of same numbers
96=(2 times 2) times (2 times 2) times 2 times 3
so now
√96=\(\sqrt{(2 times 2) times (2 times 2) times 2 times 3}\)=\(2 times 2\sqrt{2 times 3}\)=\(4\sqrt{6}\)

answer is \(4\sqrt{6}\)

√96 = √1623 =  4√6
use the rules of surds