one day, only 47 students came to practice. there were 5students marching in first row. how could the rest of students be arranged to make equal rows?
Lets solve this:-
47 - 5 = 42
42 students need to be arranged to make equal rows.
Factors of 42:- 1, 2, 3, 6, 7, 14, 21, 42
Lets divide by each Factor:-
42 ÷ 1 = 1
1 row with 42 students
42 ÷ 2 = 21
2 rows with 21 students each
42 ÷ 3 = 14
3 rows with 14 students each
42 ÷ 6 = 7
6 rows with 7 students each
42 ÷ 7 = 6
7 rows with 6 students each
42 ÷ 14 = 3
14 rows with 3 students each
42 ÷ 21 = 2
21 rows with 2 students each
42 ÷ 42 = 1
42 rows with 1 student each
So, you can make 8 equal rows:-
1 row with 42 students
2 rows with 21 students each
3 rows with 14 students each
6 rows with 7 students each
7 rows with 6 students each
14 rows with 3 students each
21 rows with 2 students each
42 rows with 1 student each
Hope I helped ya!! xD
if there were 5 in the first row. There could be 3 more rows or 14. I hope I am understanding the question correctly.