Verified Answer :

konrad509

\((-5 + 3i) (1- 2i)=\\ -5+10i+3i+6=\\ 1+13i\)

\((-5+3i)\cdot(1-2i)\\\\=-5+10i+3i-6i^2\\\\=-5+13i-6(-1)\\\\=-5+13i+6\\\\=\boxed{1+13i}\)


\(i=\sqrt{-1}\to i^2=-1\)

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