Answer:
B. 100 J
Explanation:
The change in potential energy of an object is given by:
\(\Delta U= W \Delta h\)
where
W is the weight of the object
\(\Delta h\) is the variation of height of the object
In this problem, the weight of the baseball is W=10 N, while the variation of height is \(\Delta h=10 m\). So, the increase in potential energy of the ball is
\(\Delta U=(10 N)(10 m)=100 J\)
