The correct answer for this question is 22.32 g H2O. First, we need to
establish the mass of H2O, which is H2O = 2 (1.00G H) + (16.00g O),
which is equal to 18.00g/mol. Using factor labels you can then match and eliminate the labels of each number. 18.00g I 1.24
mol------------I----------------1 mol. Here we can observe that the mols
cancel each other out, so this means that as a result you are left with
18.00gx1.24, which gets you to your answer of 22.32g H2O.
