Web Analytics

Verified Answer :

MattD

\(ax^2+bx+c=0\)
\(x^2+6x=56\)
\(x^2+6x-56=0\)
a=1    b=6    c=-56
\(\Delta=b^2-4ac=6^2-4*1(-56)=36+224=260\)
\(\sqrt{\Delta}=2\sqrt{65}\)
\(x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-2\sqrt{65}}{2*1}=-3-\sqrt{65}\)
\(x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+2\sqrt{65}}{2*1}=-3+\sqrt{65}\)

x+6x=56

7x=56

x= 8

So, x is equal to 8