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08-02-2014
Chemistry

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how many occupied orbitals does a fluorine atom contain in the ground state?

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Anonymous Anonymous

08-02-2014

Well, the configuration is \(1s^22s^22p^5\). To show the electrons, we have 1s as [], 2s as [], 2p as [][][-], where is an electron and - is a vacant slot. We have 5 occupied orbitals (4 fully occupied, one partially occupied)

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