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anghanm9onkey2 anghanm9onkey2
  • 06-01-2016
  • Mathematics
Answered

The sides of an isosceles triangle are 5, 5, and 7. Find the measure of the vertex angle to the nearest degree.

Verified Answer :

pingwin09
pingwin09 pingwin09
  • 06-01-2016

You can use the cosine law with the formula:
a^2 = b^2 + c^2 - 2bccosA
With a = 5, b = 5, c = 7,
7^2 = 5^2 + 5^2 - 257cosA
49 = 25 + 25 - 70cosA
70cosA = 25 + 25 - 49
70*cosA = 1
cosA = 1/70
A = arccos (1/70) = 89.18 deg = 89 deg

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