Jim, Carla and Tomy are members of the same family. Carla is 5 years older than Jim. Tomy is 6 years older than Carla. The sum of their 3 ages is 31 years. How old is each one of them?
x - Jim
y - Carla
z - Tomy
\(y=x+5\\
z=y+6\\
x+y+z=31\\\\
x=y-5\\
z=y+6\\
x+y+z=31\\\\
y-5+y+y+6=31\\
3y=30\\
y=10\\\\
x=10-5\\
x=5\\\\
z=10+6\\
z=16\)
let the age of jim be x
carla's age= x+5
tomy's age= 6+5+x
sum of their ages=31
x+x+5+x+5+6=3x+16=31
3x=31-16
=15
x=15 divided by 3
= 5
jim's age=5
carla's age=10
tomy's age = 16