Answer:
\(W = 1.6 \times 10^{-17} J\)
Explanation:
Work done to move a charge through a given potential difference is
\(W = q(\Delta V)\)
here
q = magnitude of charge
\(\Delta V\) = potential difference
here it is given that charge of the particle is same as charge of proton
\(q = 1.6 \times 10^{-19} C\)
\(\Delta V = 100 V\)
now we have
\(W = (1.6 \times 10^{-19}) (100)\)
\(W = 1.6 \times 10^{-17} J\)
