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A distance of 1.0 × 10^−2 meter separates successive

crests of a periodic wave produced in a shallow

tank of water. If a crest passes a point in the tank

every 4.0 × 10^−1 second, what is the speed of this

wave?

(1) 2.5 × 10^−4 m/s (3) 2.5 × 10^−2 m/s

(2) 4.0 × 10^−3 m/s (4) 4.0 × 10^−1 m/s

Verified Answer :

TaylorBayley

There are 2 formulae you will need to use in this question, v=flambda where f is the frequency and lambda is the wavelength. The second one is f=1/T where f is the frequency and T is the time.

Firstly, let's work out f:

f=1/(410^-1)=2.5Hz

Then, we can substitute it into the second equation to work out the speed:

v=2.5(110^-2)=0.025= 2.5*10^-2 m/s

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