\(2x^2+ 9x=-5 \\ \\2x^2 + 9x+5 =0 \\\\a=2, \ \ b=9 , \ \ c=5 \\\\\Delta =b^2-4ac = 9^2 -4\cdot 2\cdot 5 = 81-40=41 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{41}}{2\cdot 2 }=\frac{-9-\sqrt{41}}{ 4 }\\\\ x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{41}}{2\cdot 2 }=\frac{-9+\sqrt{41}}{4 }\)
