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gurmehar
gurmehar gurmehar
  • 20-07-2014
  • Mathematics
Answered

if a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.

Verified Answer :

Anonymous Anonymous
  • 23-07-2014

according to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2a/bca+b2b/cab+c2c/abc=3
cancel a,b,c in   all the fraction then you get
a²/bc+b²/ca+c²/ab=3. 
hence proved


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