Verified Answer :

mathwiz916

48a^3 bc^2 / (3abc) = 16a^2c

JeanaShupp

Answer: \(16a^2c\)

Step-by-step explanation:

Given division problem: \(48a^3bc^2\div48a^3bc^2\)

It can be written as :

\(\frac{48a^3bc^2}{3abc}\)

Since,  \(48=3\times16\)

Divide 3 from numerator and denominator we get,

\(\frac{16a^3bc^2}{abc}\)

The division law of exponent says that

\(\frac{a^m}{a^n}=a^{m-n}\)

Therefore, \(\frac{16a^3bc^2}{abc}=16a^{3-1}b^{1-1}c^{2-1}=16a^2b^0c^1=16a^2c\)

Hence, \(48a^3bc^2\div48a^3bc^2=16a^2c\)

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