The standard baseball measures 2 11/16" in diameter. What is its volume (to the nearest hundredth)?
if the diameter = 2+11/16 inches, radius=diameter/2= 1+11/32 inches
volume of a sphere is (4/3)pi*r^3 = 10.16
Answer:
\(10.16\) inch³
Step-by-step explanation:
The shape of a baseball is sphere. Given that, the diameter of the baseball is \(2\dfrac{11}{16}\) inches.
So radius will be,
\(=\dfrac{2\frac{11}{16}}{2}\)
\(=\dfrac{\frac{43}{16}}{2}\)
\(=\dfrac{43}{32}\) inches.
We know that, the volume of a sphere is,
\(V_{sphere}=\dfrac{4}{3}\pi r^3\)
\(=\dfrac{4}{3}\pi \left(\dfrac{43}{32}\right )^3\)
\(=10.163\appox =10.16\) inch³