Verified Answer :

\(\sqrt{2x^2}:\sqrt{5x}\\\\2x^2\geq0\ \wedge\ x > 0\\\\x^2\geq0\ \wedge\ x > 0\\\\x\in\mathbb{R}\ \wedge\ x > 0\Rightarrow x > 0\ (x\in\mathbb{R^+})\\\\Answer:c.\ x > 0\)

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Answer:

x>0

Step-by-step explanation:

Ap Ex:)

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