Simplify 8 -2/3 please (leave as fraction)
\(8^{-\frac{2}{3}}=\\ \left(\frac{1}{8}\right)^{\frac{2}{3}}=\\ \sqrt[3]{\left(\frac{1}{8}\right)^2}=\\ \sqrt[3]{\frac{1}{64}}=\\ \frac{1}{4}\)
\(8^{-\frac{2}{3}}=\left(2^3\right)^{-\frac{2}{3}}=2^{3\cdot(-\frac{2}{3})}=2^{-2}=\left(\frac{1}{2}\right)^2=\frac{1}{4}\)
