Verified Answer :

iloveonedirection

\(y=x^2-1\)

\(0=x^2-1\)

\(0=(x+1)(x-1)\)

\(x+1=0\)

\(x=-1\)

\(x-1=0\)

\(x=1\)

\(zeros:-1,1\)

AL2006

y = x² - 1

I can find the zeros from a graph, but that won't help you any, because
I'm not about to draw the graph and then post it here.

y = (x + 1) (x - 1)

y = 0 when x = +1 or x = -1.

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