iwise004 iwise004

23-06-2014
Mathematics

Answered

I need to find the zeros of the function:

f(x)=2x^2-5x-3

Verified Answer :

konrad509 konrad509

23-06-2014

\(2x^2-5x-3=0\\ 2x^2-2x-3x-3=0\\ 2x(x+1)-3(x+1)=0\\ (2x-3)(x+1)=0\\ x=\frac{3}{2} \vee x=-1\)

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