a⁴+b⁴=a²b² ,prove that a⁶+b⁶=0
\(a^4+b^4=a^2b^2\\ a^4-a^2b^2+b^4=0\\ a^4-2a^2b^2+b^4+a^2b^2=0\\ (a^2+b^2)^2=-a^2b^2\)The only possible option is that \(a^2+b^2=0 \wedge a^2b^2=0\\\) and this condition is met only when \(a=0 \wedge b=0\).\(0^6+0^6=0\\ 0=0\)
