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coolraymond1234
coolraymond1234 coolraymond1234
  • 10-11-2015
  • Mathematics
Answered

At noon the outside temperature was –5°F. By 4 p.m. the same day, the temperature had dropped 13°F. What was the outside temperature at 4 p.m.? At 4 p.m. the outside temperature was °F.

Verified Answer :

Anonymous Anonymous
  • 10-11-2015

-5 + (-13) = -18ºF
Good luck!

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homesicklovedserene
homesicklovedserene homesicklovedserene
  • 10-11-2015

the temperature turned to -18°F
-5-13=-18

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