Verified Answer :

\(y=2x-3\\\\(0;-3)\to x=0;\ y=-3\\L=-3;\ R=2\cdot0-3=-3\\L=R\\Point\ (0;-3)\ is\ on\ the\ line\\\\(1;2)\to x=1;\ y=2\\L=2;\ R=2\cdot1-3=2-3=-1\\L eq R\\Point\ (1;2)\ isn't\ on\ the\ line\\\\(2;1)\to x=2;\ y=1\\L=1;\ R=2\cdot2-3=4-3=1\\L=R\\Point\ (2;1)\ in\ on\ the\ line\\\\Answer:(0;-3);\ (2;1)\)

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