Verified Answer :

Ryan2

\(x(x+1)=22952\\ \\ x^2+x-22952=0\\ \\ \Delta=1^2-4.1.(-22952)=1+91808=91809\\ \\ x=\frac{-1+\sqrt{91809}}{2}=\frac{-1+303}{2}=\frac{302}{2}=151\)

Numbers are: 151 and 152

konrad509

\(n(n+1)=22952\\ n^2+n-22952=0\\ \Delta=1^2-4\cdot1\cdot(-22952)=91809\\ \sqrt{\Delta}=\sqrt{91809}=303\\ n_1=\frac{-1-303}{2\cdot1}=\frac{-304}{2}=-152\\ n_2=\frac{-1+303}{2\cdot1}=\frac{302}{2}=151\\\\ n_1+1=-152+1=-151\\ n_2+1=151+1=152\)

Those numbers are -152 and -151 or 151 and 152.

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