Solve for x/4-x+2/6=x/3
\(\frac{x}{4} -\frac{ x+ 2 }{6} = \frac{x}{3} \ \ \cdot 12\\ \\3x-2(x+2)=4x\\ \\3x-2x-4=4x \\ \\3x-2x-4x=4 \\ \\-3x =4\ \ / :(-3)\\ \\x=-\frac{4}{3}\\ \\x=-1\frac{1}{3}\)
\(\frac{x}{4} - \frac{x+2}{6} = \frac{1}{3} \ /\cdot12\\\\ \frac{x}{4}\cdot12 - \frac{x+2}{6}\cdot12 = \frac{1}{3}\cdot12\\\\3x-2(x+2)=4\\\\3x-2x-4=4\\\\x=8\)
