what are 2 ways to solve 20=-5(-3+x)
1) First way:
\(-5(-3+x) = 20\)
=> \(15 - 5x = 20\)
=> \(-5x = 20 -15\)
=> \(-5x = 5\)
=> \(x = 5/-5\)
=> \(x = -1\)
2) Second way:
\(-5(-3+x)=20\)
=> \(-3+x = 20/-5\)
=> \(- 3 + x = -4\)
=> \(x = -4 + 3\)
=> \(x = -1\)
1) 20 = -5(-3+x)
20/-5 = -3 + x
-4 = -3 + x
-4 + 3 = x
x = -1
2)20 = -5(-3 + x)
20 = 15 - 5x
20 - 15 = - 5x
5 = -5x
5/-5 = x
x = -1